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(A) The electric field is given as $\vec E = a\hat i + b\hat j$.The area vector $\vec S$ for a square of side $l$ parallel to the $y-z$ plane is direc

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$al^2$

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(A) The electric field is given as $\vec E = a\hat i + b\hat j$.The area vector $\vec S$ for a square of side $l$ parallel to the $y-z$ plane is directed along the $x$-axis,so $\vec S = l^2\hat i$.The electric flux $\phi$ is defined as the dot product of the electric field and the area vector: $\phi = \vec E \cdot \vec S$.Substituting the values: $\phi = (a\hat i + b\hat j) \cdot (l^2\hat i)$.Since $\hat i \cdot \hat i = 1$ and $\hat j \cdot \hat i = 0$,we get $\phi = a \cdot l^2 + 0 = al^2$.

The electric field in a region is given by $\vec E = a\hat i + b\hat j$. Here $a$ and $b$ are constants. Find the net flux passing through a square area of side $l$ parallel to the $y-z$ plane.

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